Find the value of k Given: (k – 1)x – y = 5 – eq 1 (k + 1)x + (1 – k)y = (3k + 1) – eq 2

Given:

 (k – 1)x – y = 5 – eq 1 

 (k + 1)x + (1 – k)y = (3k + 1) – eq 2 

 Here, a1 = (k - 1), b1 = - 1, c1 = - 5

a2 = (k + 1) , b2 = (1 - k), c2 = - (3k + 1)

Given that system of equations has infinitely many solution

∴  =  = 

 =  = 

Here,

 = 

(3k + 1) = - 5×(1 - k)

3k + 1 = - 5 + 5k

5K – 3k = 1 + 5

2k = 6

k = 

k = 3

∴ k = 3